Encyclopedia of Crystallographic Prototypes

AFLOW Prototype: A6B6C_hP39_191_io_ehjk_ad-001

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LiFe$_{6}$Ge$_{6}$ Structure: A6B6C_hP39_191_io_ehjk_ad-001

Picture of Structure; Click for Big Picture
Prototype Fe$_{6}$Ge$_{6}$Li
AFLOW prototype label A6B6C_hP39_191_io_ehjk_ad-001
ICSD 41384
CCDC 1611167
Pearson symbol hP39
Space group number 191
Space group symbol $P6/mmm$
AFLOW prototype command aflow --proto=A6B6C_hP39_191_io_ehjk_ad-001
--params=$a, \allowbreak c/a, \allowbreak z_{3}, \allowbreak z_{4}, \allowbreak z_{5}, \allowbreak x_{6}, \allowbreak x_{7}, \allowbreak x_{8}, \allowbreak z_{8}$

Other compounds with this structure

LiNi$_{6}$Ge$_{6}$,  LiNi$_{6}$Si$_{6}$


  • All of the LiFe$_{x}$Ge$_{x}$ structures are Kagome compounds with the iron, germanium, and lithium/germanium layers all having trihexagonal tiling.

\[ \begin{array}{ccc} \mathbf{a_{1}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a \,\mathbf{\hat{y}}\\\mathbf{a_{2}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a \,\mathbf{\hat{y}}\\\mathbf{a_{3}}&=&c \,\mathbf{\hat{z}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $0$ = $0$ (1a) Li I
$\mathbf{B_{2}}$ = $\frac{1}{3} \, \mathbf{a}_{1}+\frac{2}{3} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (2d) Li II
$\mathbf{B_{3}}$ = $\frac{2}{3} \, \mathbf{a}_{1}+\frac{1}{3} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (2d) Li II
$\mathbf{B_{4}}$ = $z_{3} \, \mathbf{a}_{3}$ = $c z_{3} \,\mathbf{\hat{z}}$ (2e) Ge I
$\mathbf{B_{5}}$ = $- z_{3} \, \mathbf{a}_{3}$ = $- c z_{3} \,\mathbf{\hat{z}}$ (2e) Ge I
$\mathbf{B_{6}}$ = $\frac{1}{3} \, \mathbf{a}_{1}+\frac{2}{3} \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+c z_{4} \,\mathbf{\hat{z}}$ (4h) Ge II
$\mathbf{B_{7}}$ = $\frac{2}{3} \, \mathbf{a}_{1}+\frac{1}{3} \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+c z_{4} \,\mathbf{\hat{z}}$ (4h) Ge II
$\mathbf{B_{8}}$ = $\frac{2}{3} \, \mathbf{a}_{1}+\frac{1}{3} \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}- c z_{4} \,\mathbf{\hat{z}}$ (4h) Ge II
$\mathbf{B_{9}}$ = $\frac{1}{3} \, \mathbf{a}_{1}+\frac{2}{3} \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}- c z_{4} \,\mathbf{\hat{z}}$ (4h) Ge II
$\mathbf{B_{10}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+z_{5} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{4}a \,\mathbf{\hat{y}}+c z_{5} \,\mathbf{\hat{z}}$ (6i) Fe I
$\mathbf{B_{11}}$ = $\frac{1}{2} \, \mathbf{a}_{2}+z_{5} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{4}a \,\mathbf{\hat{y}}+c z_{5} \,\mathbf{\hat{z}}$ (6i) Fe I
$\mathbf{B_{12}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}+z_{5} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+c z_{5} \,\mathbf{\hat{z}}$ (6i) Fe I
$\mathbf{B_{13}}$ = $\frac{1}{2} \, \mathbf{a}_{2}- z_{5} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{4}a \,\mathbf{\hat{y}}- c z_{5} \,\mathbf{\hat{z}}$ (6i) Fe I
$\mathbf{B_{14}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- z_{5} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{4}a \,\mathbf{\hat{y}}- c z_{5} \,\mathbf{\hat{z}}$ (6i) Fe I
$\mathbf{B_{15}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}- z_{5} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- c z_{5} \,\mathbf{\hat{z}}$ (6i) Fe I
$\mathbf{B_{16}}$ = $x_{6} \, \mathbf{a}_{1}$ = $\frac{1}{2}a x_{6} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{6} \,\mathbf{\hat{y}}$ (6j) Ge III
$\mathbf{B_{17}}$ = $x_{6} \, \mathbf{a}_{2}$ = $\frac{1}{2}a x_{6} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{6} \,\mathbf{\hat{y}}$ (6j) Ge III
$\mathbf{B_{18}}$ = $- x_{6} \, \mathbf{a}_{1}- x_{6} \, \mathbf{a}_{2}$ = $- a x_{6} \,\mathbf{\hat{x}}$ (6j) Ge III
$\mathbf{B_{19}}$ = $- x_{6} \, \mathbf{a}_{1}$ = $- \frac{1}{2}a x_{6} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{6} \,\mathbf{\hat{y}}$ (6j) Ge III
$\mathbf{B_{20}}$ = $- x_{6} \, \mathbf{a}_{2}$ = $- \frac{1}{2}a x_{6} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{6} \,\mathbf{\hat{y}}$ (6j) Ge III
$\mathbf{B_{21}}$ = $x_{6} \, \mathbf{a}_{1}+x_{6} \, \mathbf{a}_{2}$ = $a x_{6} \,\mathbf{\hat{x}}$ (6j) Ge III
$\mathbf{B_{22}}$ = $x_{7} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}a x_{7} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{7} \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (6k) Ge IV
$\mathbf{B_{23}}$ = $x_{7} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}a x_{7} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{7} \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (6k) Ge IV
$\mathbf{B_{24}}$ = $- x_{7} \, \mathbf{a}_{1}- x_{7} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $- a x_{7} \,\mathbf{\hat{x}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (6k) Ge IV
$\mathbf{B_{25}}$ = $- x_{7} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{3}$ = $- \frac{1}{2}a x_{7} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{7} \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (6k) Ge IV
$\mathbf{B_{26}}$ = $- x_{7} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $- \frac{1}{2}a x_{7} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{7} \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (6k) Ge IV
$\mathbf{B_{27}}$ = $x_{7} \, \mathbf{a}_{1}+x_{7} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $a x_{7} \,\mathbf{\hat{x}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (6k) Ge IV
$\mathbf{B_{28}}$ = $x_{8} \, \mathbf{a}_{1}+2 x_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $\frac{3}{2}a x_{8} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{29}}$ = $- 2 x_{8} \, \mathbf{a}_{1}- x_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $- \frac{3}{2}a x_{8} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{30}}$ = $x_{8} \, \mathbf{a}_{1}- x_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $- \sqrt{3}a x_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{31}}$ = $- x_{8} \, \mathbf{a}_{1}- 2 x_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $- \frac{3}{2}a x_{8} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{32}}$ = $2 x_{8} \, \mathbf{a}_{1}+x_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $\frac{3}{2}a x_{8} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{33}}$ = $- x_{8} \, \mathbf{a}_{1}+x_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $\sqrt{3}a x_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{34}}$ = $2 x_{8} \, \mathbf{a}_{1}+x_{8} \, \mathbf{a}_{2}- z_{8} \, \mathbf{a}_{3}$ = $\frac{3}{2}a x_{8} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{35}}$ = $- x_{8} \, \mathbf{a}_{1}- 2 x_{8} \, \mathbf{a}_{2}- z_{8} \, \mathbf{a}_{3}$ = $- \frac{3}{2}a x_{8} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{36}}$ = $- x_{8} \, \mathbf{a}_{1}+x_{8} \, \mathbf{a}_{2}- z_{8} \, \mathbf{a}_{3}$ = $\sqrt{3}a x_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{37}}$ = $- 2 x_{8} \, \mathbf{a}_{1}- x_{8} \, \mathbf{a}_{2}- z_{8} \, \mathbf{a}_{3}$ = $- \frac{3}{2}a x_{8} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{38}}$ = $x_{8} \, \mathbf{a}_{1}+2 x_{8} \, \mathbf{a}_{2}- z_{8} \, \mathbf{a}_{3}$ = $\frac{3}{2}a x_{8} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a x_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II
$\mathbf{B_{39}}$ = $x_{8} \, \mathbf{a}_{1}- x_{8} \, \mathbf{a}_{2}- z_{8} \, \mathbf{a}_{3}$ = $- \sqrt{3}a x_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (12o) Fe II

References

    \newcommand{\Ozolins}{Ozoli{ņ}{š}}\begin{thebibliography}{1}\expandafter\ifx\csname urlstyle\endcsname\relax \providecommand{\doi}[1]{doi:\discretionary{}{}{}#1}\else \providecommand{\doi}{doi:\discretionary{}{}{}\begingroup \urlstyle{rm}\Url}\fi\providecommand{\selectlanguage}[1]{\relax}\providecommand{\bibAnnoteFile}[1]{% \IfFileExists{#1}{\begin{quotation}\noindent\textsc{Key:} #1\ \textsc{Annotation:} \input{#1}\end{quotation}}{}}\providecommand{\bibAnnote}[2]{% \begin{quotation}\noindent\textsc{Key:} #1\ \textsc{Annotation:} #2\end{quotation}}\bibitem{LiFe6Ge6/Welk_ZAAC_424_193_1976}E. Welk and H.-U. Schuster, Zur Kenntnis der Phase LiFe$_{6}$Ge$_{6}$}, Z. Anorganische und Allgemeine Chemie 424, 193–197 (1976), doi:10.1002/zaac.19764240302.\bibAnnoteFile{LiFe6Ge6/Welk_ZAAC_424_193_1976

Found in

  • A. Mantravadi, R. A. Ribeiro, S. L. Bud'ko, P. C. Canfield, and J. V. Zaikina, Experimental Testing of the Theoretically Predicted Magnetic Properties for Kagomé Compounds in the Li-Fe-Ge System, Inorg. Chem. 63, 24697–24708 (2024), doi:10.1021/acs.inorgchem.4c03925.

First cited in

  • N. Anderson, M. J. Mehl, H. Eckert, S. Divilov, X. Campilongo, S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 5. Submitted to Computational Materials Science (2026).

Geometry files


Prototype Generator

aflow --proto=A6B6C_hP39_191_io_ehjk_ad --params=$a,c/a,z_{3},z_{4},z_{5},x_{6},x_{7},x_{8},z_{8}$

Species:

Running:

Output: