Ga$_{3}$Ni$_{3}$Zn Structure: A3B3C_cI112_230_f_g_a-001

Picture of Structure; Click for Big Picture
Prototype Ga$_{3}$Ni$_{3}$Zn
AFLOW prototype label A3B3C_cI112_230_f_g_a-001
ICSD 103898
CCDC 1661829
Pearson symbol cI112
Space group number 230
Space group symbol $Ia\overline{3}d$
AFLOW prototype command aflow --proto=A3B3C_cI112_230_f_g_a-001
--params=$a, \allowbreak x_{2}, \allowbreak y_{3}$


\[ \begin{array}{ccc} \mathbf{a_{1}}&=&- \frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}\\\mathbf{a_{2}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}\\\mathbf{a_{3}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}}- \frac{1}{2}a \,\mathbf{\hat{z}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $0$ = $0$ (16a) Zn I
$\mathbf{B_{2}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{y}}$ (16a) Zn I
$\mathbf{B_{3}}$ = $\frac{1}{2} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}$ (16a) Zn I
$\mathbf{B_{4}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}$ = $\frac{1}{2}a \,\mathbf{\hat{z}}$ (16a) Zn I
$\mathbf{B_{5}}$ = $\frac{1}{2} \, \mathbf{a}_{1}$ = $- \frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (16a) Zn I
$\mathbf{B_{6}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (16a) Zn I
$\mathbf{B_{7}}$ = $\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}- \frac{1}{4}a \,\mathbf{\hat{z}}$ (16a) Zn I
$\mathbf{B_{8}}$ = $\frac{1}{2} \, \mathbf{a}_{2}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}- \frac{1}{4}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (16a) Zn I
$\mathbf{B_{9}}$ = $\frac{1}{4} \, \mathbf{a}_{1}+\left(x_{2} + \frac{1}{4}\right) \, \mathbf{a}_{2}+x_{2} \, \mathbf{a}_{3}$ = $a x_{2} \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{10}}$ = $\frac{3}{4} \, \mathbf{a}_{1}- \left(x_{2} - \frac{1}{4}\right) \, \mathbf{a}_{2}- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a x_{2} \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{11}}$ = $x_{2} \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}+\left(x_{2} + \frac{1}{4}\right) \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+a x_{2} \,\mathbf{\hat{y}}$ (48f) Ga I
$\mathbf{B_{12}}$ = $- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}- \left(x_{2} - \frac{1}{4}\right) \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}- a x_{2} \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{13}}$ = $\left(x_{2} + \frac{1}{4}\right) \, \mathbf{a}_{1}+x_{2} \, \mathbf{a}_{2}+\frac{1}{4} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{y}}+a x_{2} \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{14}}$ = $- \left(x_{2} - \frac{1}{4}\right) \, \mathbf{a}_{1}- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{2}+\frac{3}{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}- a x_{2} \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{15}}$ = $\left(x_{2} + \frac{1}{4}\right) \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}+x_{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{16}}$ = $- \left(x_{2} - \frac{1}{4}\right) \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}- a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{y}}$ (48f) Ga I
$\mathbf{B_{17}}$ = $\frac{3}{4} \, \mathbf{a}_{1}+x_{2} \, \mathbf{a}_{2}+\left(x_{2} + \frac{1}{4}\right) \, \mathbf{a}_{3}$ = $a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{18}}$ = $\frac{1}{4} \, \mathbf{a}_{1}- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{2}- \left(x_{2} - \frac{1}{4}\right) \, \mathbf{a}_{3}$ = $- a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{19}}$ = $- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{1}- \left(x_{2} - \frac{1}{4}\right) \, \mathbf{a}_{2}+\frac{1}{4} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{y}}- a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{20}}$ = $x_{2} \, \mathbf{a}_{1}+\left(x_{2} + \frac{1}{4}\right) \, \mathbf{a}_{2}+\frac{3}{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}+a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{21}}$ = $\frac{3}{4} \, \mathbf{a}_{1}- \left(x_{2} - \frac{3}{4}\right) \, \mathbf{a}_{2}- x_{2} \, \mathbf{a}_{3}$ = $- a x_{2} \,\mathbf{\hat{x}}+\frac{3}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{22}}$ = $\frac{1}{4} \, \mathbf{a}_{1}+\left(x_{2} + \frac{3}{4}\right) \, \mathbf{a}_{2}+\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a \left(x_{2} + \frac{1}{2}\right) \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{23}}$ = $- x_{2} \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}- \left(x_{2} - \frac{3}{4}\right) \, \mathbf{a}_{3}$ = $\frac{3}{4}a \,\mathbf{\hat{x}}- a x_{2} \,\mathbf{\hat{y}}$ (48f) Ga I
$\mathbf{B_{24}}$ = $\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}+\left(x_{2} + \frac{3}{4}\right) \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+a \left(x_{2} + \frac{1}{2}\right) \,\mathbf{\hat{y}}$ (48f) Ga I
$\mathbf{B_{25}}$ = $- \left(x_{2} - \frac{3}{4}\right) \, \mathbf{a}_{1}- x_{2} \, \mathbf{a}_{2}+\frac{3}{4} \, \mathbf{a}_{3}$ = $\frac{3}{4}a \,\mathbf{\hat{y}}- a x_{2} \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{26}}$ = $\left(x_{2} + \frac{3}{4}\right) \, \mathbf{a}_{1}+\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{2}+\frac{1}{4} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{y}}+a \left(x_{2} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{27}}$ = $- \left(x_{2} - \frac{3}{4}\right) \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}- x_{2} \, \mathbf{a}_{3}$ = $- \frac{1}{4}a \,\mathbf{\hat{x}}- a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{28}}$ = $\left(x_{2} + \frac{3}{4}\right) \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}+\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+a \left(x_{2} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{29}}$ = $\frac{1}{4} \, \mathbf{a}_{1}- x_{2} \, \mathbf{a}_{2}- \left(x_{2} - \frac{3}{4}\right) \, \mathbf{a}_{3}$ = $- a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}}- \frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{30}}$ = $\frac{3}{4} \, \mathbf{a}_{1}+\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{2}+\left(x_{2} + \frac{3}{4}\right) \, \mathbf{a}_{3}$ = $a \left(x_{2} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{31}}$ = $\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{1}+\left(x_{2} + \frac{3}{4}\right) \, \mathbf{a}_{2}+\frac{3}{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}+a \left(x_{2} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{32}}$ = $- x_{2} \, \mathbf{a}_{1}- \left(x_{2} - \frac{3}{4}\right) \, \mathbf{a}_{2}+\frac{1}{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{1}{4}a \,\mathbf{\hat{y}}- a \left(x_{2} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48f) Ga I
$\mathbf{B_{33}}$ = $\frac{1}{4} \, \mathbf{a}_{1}- \left(y_{3} - \frac{3}{8}\right) \, \mathbf{a}_{2}+\left(y_{3} + \frac{1}{8}\right) \, \mathbf{a}_{3}$ = $\frac{1}{8}a \,\mathbf{\hat{x}}+a y_{3} \,\mathbf{\hat{y}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{34}}$ = $- \left(2 y_{3} - \frac{3}{4}\right) \, \mathbf{a}_{1}- \left(y_{3} - \frac{1}{8}\right) \, \mathbf{a}_{2}- \left(y_{3} - \frac{3}{8}\right) \, \mathbf{a}_{3}$ = $- \frac{1}{8}a \,\mathbf{\hat{x}}- a \left(y_{3} - \frac{1}{2}\right) \,\mathbf{\hat{y}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{35}}$ = $\left(2 y_{3} + \frac{3}{4}\right) \, \mathbf{a}_{1}+\left(y_{3} + \frac{1}{8}\right) \, \mathbf{a}_{2}+\left(y_{3} + \frac{3}{8}\right) \, \mathbf{a}_{3}$ = $- \frac{1}{8}a \,\mathbf{\hat{x}}+a \left(y_{3} + \frac{1}{2}\right) \,\mathbf{\hat{y}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{36}}$ = $\frac{1}{4} \, \mathbf{a}_{1}+\left(y_{3} + \frac{3}{8}\right) \, \mathbf{a}_{2}- \left(y_{3} - \frac{1}{8}\right) \, \mathbf{a}_{3}$ = $\frac{1}{8}a \,\mathbf{\hat{x}}- a y_{3} \,\mathbf{\hat{y}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{37}}$ = $\left(y_{3} + \frac{1}{8}\right) \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}- \left(y_{3} - \frac{3}{8}\right) \, \mathbf{a}_{3}$ = $- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{1}{8}a \,\mathbf{\hat{y}}+a y_{3} \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{38}}$ = $- \left(y_{3} - \frac{3}{8}\right) \, \mathbf{a}_{1}- \left(2 y_{3} - \frac{3}{4}\right) \, \mathbf{a}_{2}- \left(y_{3} - \frac{1}{8}\right) \, \mathbf{a}_{3}$ = $- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{x}}- \frac{1}{8}a \,\mathbf{\hat{y}}- a \left(y_{3} - \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{39}}$ = $\left(y_{3} + \frac{3}{8}\right) \, \mathbf{a}_{1}+\left(2 y_{3} + \frac{3}{4}\right) \, \mathbf{a}_{2}+\left(y_{3} + \frac{1}{8}\right) \, \mathbf{a}_{3}$ = $a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{x}}- \frac{1}{8}a \,\mathbf{\hat{y}}+a \left(y_{3} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{40}}$ = $- \left(y_{3} - \frac{1}{8}\right) \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}+\left(y_{3} + \frac{3}{8}\right) \, \mathbf{a}_{3}$ = $a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{1}{8}a \,\mathbf{\hat{y}}- a y_{3} \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{41}}$ = $- \left(y_{3} - \frac{3}{8}\right) \, \mathbf{a}_{1}+\left(y_{3} + \frac{1}{8}\right) \, \mathbf{a}_{2}+\frac{1}{4} \, \mathbf{a}_{3}$ = $a y_{3} \,\mathbf{\hat{x}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{1}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{42}}$ = $- \left(y_{3} - \frac{1}{8}\right) \, \mathbf{a}_{1}- \left(y_{3} - \frac{3}{8}\right) \, \mathbf{a}_{2}- \left(2 y_{3} - \frac{3}{4}\right) \, \mathbf{a}_{3}$ = $- a \left(y_{3} - \frac{1}{2}\right) \,\mathbf{\hat{x}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{y}}- \frac{1}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{43}}$ = $\left(y_{3} + \frac{1}{8}\right) \, \mathbf{a}_{1}+\left(y_{3} + \frac{3}{8}\right) \, \mathbf{a}_{2}+\left(2 y_{3} + \frac{3}{4}\right) \, \mathbf{a}_{3}$ = $a \left(y_{3} + \frac{1}{2}\right) \,\mathbf{\hat{x}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{y}}- \frac{1}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{44}}$ = $\left(y_{3} + \frac{3}{8}\right) \, \mathbf{a}_{1}- \left(y_{3} - \frac{1}{8}\right) \, \mathbf{a}_{2}+\frac{1}{4} \, \mathbf{a}_{3}$ = $- a y_{3} \,\mathbf{\hat{x}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{1}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{45}}$ = $\frac{3}{4} \, \mathbf{a}_{1}+\left(y_{3} + \frac{5}{8}\right) \, \mathbf{a}_{2}- \left(y_{3} - \frac{7}{8}\right) \, \mathbf{a}_{3}$ = $\frac{3}{8}a \,\mathbf{\hat{x}}- a \left(y_{3} - \frac{1}{2}\right) \,\mathbf{\hat{y}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{46}}$ = $\left(2 y_{3} + \frac{1}{4}\right) \, \mathbf{a}_{1}+\left(y_{3} + \frac{7}{8}\right) \, \mathbf{a}_{2}+\left(y_{3} + \frac{5}{8}\right) \, \mathbf{a}_{3}$ = $\frac{5}{8}a \,\mathbf{\hat{x}}+a y_{3} \,\mathbf{\hat{y}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{47}}$ = $- \left(2 y_{3} - \frac{1}{4}\right) \, \mathbf{a}_{1}- \left(y_{3} - \frac{7}{8}\right) \, \mathbf{a}_{2}- \left(y_{3} - \frac{5}{8}\right) \, \mathbf{a}_{3}$ = $\frac{5}{8}a \,\mathbf{\hat{x}}- a y_{3} \,\mathbf{\hat{y}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{48}}$ = $\frac{3}{4} \, \mathbf{a}_{1}- \left(y_{3} - \frac{5}{8}\right) \, \mathbf{a}_{2}+\left(y_{3} + \frac{7}{8}\right) \, \mathbf{a}_{3}$ = $\frac{3}{8}a \,\mathbf{\hat{x}}+a \left(y_{3} + \frac{1}{2}\right) \,\mathbf{\hat{y}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{49}}$ = $- \left(y_{3} - \frac{7}{8}\right) \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}+\left(y_{3} + \frac{5}{8}\right) \, \mathbf{a}_{3}$ = $a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{3}{8}a \,\mathbf{\hat{y}}- a \left(y_{3} - \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{50}}$ = $\left(y_{3} + \frac{5}{8}\right) \, \mathbf{a}_{1}+\left(2 y_{3} + \frac{1}{4}\right) \, \mathbf{a}_{2}+\left(y_{3} + \frac{7}{8}\right) \, \mathbf{a}_{3}$ = $a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{5}{8}a \,\mathbf{\hat{y}}+a y_{3} \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{51}}$ = $- \left(y_{3} - \frac{5}{8}\right) \, \mathbf{a}_{1}- \left(2 y_{3} - \frac{1}{4}\right) \, \mathbf{a}_{2}- \left(y_{3} - \frac{7}{8}\right) \, \mathbf{a}_{3}$ = $- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{5}{8}a \,\mathbf{\hat{y}}- a y_{3} \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{52}}$ = $\left(y_{3} + \frac{7}{8}\right) \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}- \left(y_{3} - \frac{5}{8}\right) \, \mathbf{a}_{3}$ = $- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+\frac{3}{8}a \,\mathbf{\hat{y}}+a \left(y_{3} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{53}}$ = $\left(y_{3} + \frac{5}{8}\right) \, \mathbf{a}_{1}- \left(y_{3} - \frac{7}{8}\right) \, \mathbf{a}_{2}+\frac{3}{4} \, \mathbf{a}_{3}$ = $- a \left(y_{3} - \frac{1}{2}\right) \,\mathbf{\hat{x}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{3}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{54}}$ = $\left(y_{3} + \frac{7}{8}\right) \, \mathbf{a}_{1}+\left(y_{3} + \frac{5}{8}\right) \, \mathbf{a}_{2}+\left(2 y_{3} + \frac{1}{4}\right) \, \mathbf{a}_{3}$ = $a y_{3} \,\mathbf{\hat{x}}+a \left(y_{3} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{5}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{55}}$ = $- \left(y_{3} - \frac{7}{8}\right) \, \mathbf{a}_{1}- \left(y_{3} - \frac{5}{8}\right) \, \mathbf{a}_{2}- \left(2 y_{3} - \frac{1}{4}\right) \, \mathbf{a}_{3}$ = $- a y_{3} \,\mathbf{\hat{x}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{5}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I
$\mathbf{B_{56}}$ = $- \left(y_{3} - \frac{5}{8}\right) \, \mathbf{a}_{1}+\left(y_{3} + \frac{7}{8}\right) \, \mathbf{a}_{2}+\frac{3}{4} \, \mathbf{a}_{3}$ = $a \left(y_{3} + \frac{1}{2}\right) \,\mathbf{\hat{x}}- a \left(y_{3} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+\frac{3}{8}a \,\mathbf{\hat{z}}$ (48g) Ni I

References

  • N. Sarah, T. Rajasekharan, and K. Schubert, über die Mischung NiZnMGaM, Z. Metallkde. 72, 732–735 (1981), doi:10.1515/ijmr-1981-721013.

Found in

  • Inorganic Crystal Structure Database. Entry 103898 [Ga3Ni3Zn].

First cited in

  • N. Anderson, M. J. Mehl, H. Eckert, S. Divilov, X. Campilongo, S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 5. Submitted to Computational Materials Science (2026).

Geometry files


Prototype Generator

aflow --proto=A3B3C_cI112_230_f_g_a --params=$a,x_{2},y_{3}$

Species:

Running:

Output: